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ATB

#1 User is offline   cnszsun 

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Posted 2009-December-05, 01:02

Scoring: IMP

ps-1♣-ps-2♣
2♥-ps-3♥-dbl
ps-3♠-ps-4♠
AP

Michael Sun

#2 User is offline   gnasher 

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Posted 2009-December-05, 11:37

The final error was made by South.

If North had four spades (supposing that were allowed), he would have bid them over 3♥. Hence North can't have four spades, so South should convert 4♠ to 5♣.
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
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#3 User is offline   Codo 

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Posted 2009-December-07, 01:36

If 2 ♣ denies 4 spades, this is obvious. And this is the standard approach.
Kind Regards

Roland

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More system is not the answer...
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#4 User is offline   whereagles 

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Posted 2009-December-07, 05:31

North's approach was of the "unlucky expert" kind.

With that flattish hand and South extremely likely to have a 12-14 balanced hand (he passed 2♥, remember?), North should reason the only game that can possibly make is 3NT, so he should just bid that. If they take the 1st 5 tricks... tough luck. But in that case you weren't going to make game anyway.
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