Every table made 13 tricks here.
Opener led ♣4, then it was a solid 13 tricks on 2-1 trump break. On another table opener led ♦, then it was also a solid 13 tricks as well on 2-1 trump break. However, if opener led a ♠, does the slam depend on the position of ♣Q and ♦Q? Also, if trump break was 3-0, is this still a solid grand slam?
Also, if control-showing bid is used here, then we can know that we have all first and second round controls and bid 7♥, but how can we initiate the sequence (assuming 5 card majors and strong 1NT)?
I am thinking about
1♥ - 2♣
2♦ - 2♠
3♦ (showing 5+ ♦ and longer or equal ♥) - ??
If 2♠ is GF here, I can bid 3♥, in such case the bidding will go:
4♥ (absolutely minimum opening hand - no slam interest) - 5♣ (slam interest, 1st control in ♣)
5NT (We have already had all controls in the side suits - bid 7♥ if your trump is solid) - 7♥
However, if 2♠ is F1 here, do we have a method to initiate a control-showing sequence?
Also, what will happen if the bidding start with
1♥ - (/) - 2♣ - (3♠)?
Another table had
1♥ - (/) - 2♣ - (3♠)
4♦ - (4♠) - 5♥ - //
and another table had
1♥ - (/) - 2NT! (Jacoby 2NT) - (3♠)
4♣ - (4♠) - 5♦ - (/)
5♥ - //
None of the table who didn't respond 4NT after 1♥ opening could bid slam, after west overcalled 3♠. Is this slam biddable if west and east competed with 3♠ and 4♠?
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The partnership should be happy to declare 6♥.
It's difficult to construct plausible auctions to the grand.