- 3♣=5+C; 13+ total points
- 4♣=biddable C
- 4N=quantitative; 15-16 HCP
- 6N=16-20 HCP
Could/should 4♣ be Gerber instead?
Posted 2011-November-03, 12:16
Posted 2011-November-03, 13:24
Posted 2011-November-03, 21:15
Posted 2011-November-03, 21:27
Posted 2012-August-10, 02:56
Posted 2012-August-10, 03:56
Posted 2012-August-13, 16:24